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Microbiology Mycology f74f7c56

Gram stained periorbital exudates in severe panophthalmitis with cellulitis in an elderly diabetic shows irregular branching aseptate and broad hyphae. Which of the following is the most likely diagnosis-

A
Candida
B
Aspergillus
C
Pencillium
D
Apophysomyces species
High-Yield Explanation
1.Irregular branching aseptate and broad hyphae belong to Zygomycota phylum and cause Zygomycosis. *Zygomycota are aseptate fungi that cause serious infections, primarily in ketoacidotic diabetic patients and cancer patients. 2. Agents of Zygomycosis - - Rhizopus, Mucor, Lichtheimia (Old name: Absidia), Apophysomyces - Candida: Yeast like fungi. - Aspergillus: Narrow septate hyaline hyphae with acute angle branching molds. - Pencillium: Hyaline thin septate hyphae, vesicles are absent, and conidia arranged as brush border appearance molds.

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